Civil Engineering Exams (Principles of Structural Analysis and Design) – Page 1
#0.
Two plates each with thickness t = 16 mm are bolted
together with 6 – 22 mm diameter bolts forming a lap connection.
Bolt spacing are as follows :
S1 = 40 mm, S2 = 80 mm, S3 = 100 mm
Bolt hole diameter = 25 mm
Allowable stress :
Tensile stress on gross area of the plate = 0.60 Fy
Tensile stress on net area of the plate = 0.50 Fu
Shear stress of the bolt : Fv = 120 MPa
Bearing stress of the bolt : Fp = 1.2 Fu
Calculate the permissible tensile load P under the
following conditions.
Based on block shear strength.
A
273.70 KN
B
592 KN
C
1013.76 KN
D
504 KN
Answer: 504 KN
#1. A square footing 4m on a side is founded 1.2m below the ground surface for which the bulk unit weight of the soil is 20 Kn/cu.m, the cohesion strength is 10kpa and the angle of internal friction is 20 degrees. Under the condition f general failure, evaluate the contribution of the following ultimate soil bearing capacity in kpa. The ground water table is at a level that does not affect the unit weight of the soil. Use Terzaghi's bearing capacity factors.
A
24 to 48 kpa
B
96 to 192 kpa
C
48 to 96 kpa
D
0 24 kpa
Answer: 24 to 48 kpa
#2.
Two plates each with thickness t = 16 mm are bolted
together with 6 – 22 mm diameter bolts forming a lap connection.
Bolt spacing are as follows :
S1 = 40 mm, S2 = 80 mm, S3 = 100 mm
Bolt hole diameter = 25 mm
Allowable stress :
Tensile stress on gross area of the plate = 0.60 Fy
Tensile stress on net area of the plate = 0.50 Fu
Shear stress of the bolt : Fv = 120 MPa
Bearing stress of the bolt : Fp = 1.2 Fu
Calculate the permissible tensile load P under the
following conditions.
Based on shear capacity of bolts.
A
504 KN
B
1013.76 KN
C
592 KN
D
273.70 KN
Answer: 273.70 KN
#3. A simple supported beam 10 m. long gas an overhang of 2 m at the left support. If a highway uniform load of 9.35 kN/m and a concentrated load of 116 kN, passes thru the beam, compute the following based on influence line for maximum shear at mid span. Determine the length of the beam where the uniform load could produce maximum positive shear at the mid span.
A
7 m
B
6 m
C
5 m
D
8 m
Answer: 7 m
#4. A simple supported beam 10 m. long gas an overhang of 2 m at the left support. If a highway uniform load of 9.35 kN/m and a concentrated load of 116 kN, passes thru the beam, compute the following based on influence line for maximum shear at mid span. Determine the length of the beam where the uniform load could produce maximum negative shear at the mid span.
A
6 m
B
5 m
C
7 m
D
6.5 m
Answer: 5 m
#5. A simple supported beam 10 m. long gas an overhang of 2 m at the left support. If a highway uniform load of 9.35 kN/m and a concentrated load of 116 kN, passes thru the beam, compute the following based on influence line for maximum shear at mid span. If the concentrated load will be placed at the end of the overhang, compute the maximum shear at the mid span.
A
58 kN
B
32.2 kN
C
85 kN
D
23.2 kN
Answer: 23.2 kN
#6.
From the figure shown. Which of the following gives the thickness of plates required if the allowable bearing stress is 160 MPa.
A
7.3 mm
B
5.3 mm
C
6.4 mm
D
9.8 mm
Answer: 5.3 mm
#7.
Built-up column 10 m. long consists of W 350 x 900 with two plates welded to form a box section with respect to x-axis column is fixed, y-axis column is braced at the mid height.
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
Compute the effective slenderness ration with respect to x-axis.
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
A
37.64 mm
B
132.82 mm
C
36.02 mm
D
126.17 mm
Answer: 37.64 mm
#8.
Built-up column 10 m. long consists of W 350 x 900 with two plates welded to form a box section with respect to x-axis column is fixed, y-axis column is braced at the mid height.
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
Compute the axial load capacity.
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
A
2865.5 kN
B
2686.01 kN
C
2654.8 kN
D
2230.23 kN
Answer: 2654.8 kN
#9.
Built-up column 10 m. long consists of W 350 x 900 with two plates welded to form a box section with respect to x-axis column is fixed, y-axis column is braced at the mid height.
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
Compute the effective slenderness ratio with respect to y-axis
\(A = 11, 540 mm^2\)
\(I_x = 2.66 x 10^8 mm^4\)
\(I_y = 0.44 x 10^8 mm^4\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10mm\)
\(F_y = 248 MPa\)
A
132.82
B
36.02
C
97.16
D
37.64
Answer: 36.02
#10. A 12 mm thick steel tire, has a width of 110 mm and it has an internal diameter of 800 mm. The tire is heated and shrunk to a steel wheel 800.5 mm diameter. Modulus of elasticity E = 200GPa. Determine the tensile stress in the tire.
A
150 MPa
B
484 MPa
C
375 MPa
D
125 MPa
Answer: 125 MPa
#11. A 12 mm thick steel tire, has a width of 110 mm and it has an internal diameter of 800 mm. The tire is heated and shrunk to a steel wheel 800.5 mm diameter. Modulus of elasticity E = 200GPa. Determine the compressive pressure between the tire and the wheel.
A
1.25MPa
B
4.84 MPa
C
125 MPa
D
3.75 Mpa
Answer: 3.75 Mpa
#12. A 12 mm thick steel tire, has a width of 110 mm and it has an internal diameter of 800 mm. The tire is heated and shrunk to a steel wheel 800.5 mm diameter. Modulus of elasticity E = 200GPa. Determine the thickness of the tire to resist pressure of 1.5MPa if it has an allowable stress of 124 MPa.
A
3.75 mm
B
1.25 mm
C
2.48 mm
D
4.84 mm
Answer: 4.84 mm
#13.
A 12 m simply supported beam is provided by an additional support at mid span. The beam has a width of b = 300 mm and a total depth h = 450 mm. It is reinforced with 4 -25 mm diameter bars at tension side and 2 -25 mm diameter bars at the compression side with 70 mm cover to centroid of reinforcements. fc' = 30 MPa, fy = 415 MPa. Use 0.75 ρ b = 0.023.
Determine the depth of the rectangular stress block.
A
106.52 mm
B
196.35mm
C
266.2 mm
D
236.6 mm
Answer: 106.52 mm
#14.
A 12 m simply supported beam is provided by an additional support at mid span. The beam has a width of b = 300 mm and a total depth h = 450 mm. It is reinforced with 4 -25 mm diameter bars at tension side and 2 -25 mm diameter bars at the compression side with 70 mm cover to centroid of reinforcements. fc' = 30 MPa, fy = 415 MPa. Use 0.75 ρ b = 0.023.
Determine the nominal bending moment, Mn.
A
236.6 kN.m
B
266.2 kN.m
C
263.2 kN.m
D
226.3 kN.m
Answer: 266.2 kN.m
#15.
A 12 m simply supported beam is provided by an additional support at mid span. The beam has a width of b = 300 mm and a total depth h = 450 mm. It is reinforced with 4 -25 mm diameter bars at tension side and 2 -25 mm diameter bars at the compression side with 70 mm cover to centroid of reinforcements. fc' = 30 MPa, fy = 415 MPa. Use 0.75 ρ b = 0.023.
Determine the toatl factored uniform load including the beam weight considering moment capacity reduction of 0.90
A
26. 62 kN.m.
B
10. 52 kN.m.
C
23. 66 kN.m.
D
10.5 kN.m.
Answer: 23. 66 kN.m.
#16.
W350 mm x 90 kg/m girder 8 m. simple span carries equal concentration dead load P at every quarter points and uniform dead load, 5kN/m and live laod, 7.2 kN/m including dead weight.
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
Determine P based on flexure, Fb = 0.66 Fy
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
A
37.8 kN
B
19.89 kN
C
15.0 kN
D
35.7 kN
Answer: 37.8 kN
#17.
W350 mm x 90 kg/m girder 8 m. simple span carries equal concentration dead load P at every quarter points and uniform dead load, 5kN/m and live laod, 7.2 kN/m including dead weight.
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
Determine P based on shear, Fv = 0.40Fy
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
A
150.2 kN
B
198.93 kN
C
137.8 kN
D
138.52 kN
Answer: 198.93 kN
#18.
W350 mm x 90 kg/m girder 8 m. simple span carries equal concentration dead load P at every quarter points and uniform dead load, 5kN/m and live laod, 7.2 kN/m including dead weight.
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
Determine the additional live load base on deflection, \( y_{allow} = \frac{L}{360}\) for the chamber to offset for the dead load.
Properties:
\(A = 11, 500 mm^2\)
\(d =350 mm\)
\(b_f = 250 mm\)
\(t_f = 16 mm\)
\(t_w = 10 mm\)
\(I_x = 266 x 10^6\)
\(I_y = 45 x 10^6\)
\(F_y = 245 MPa\)
\(E = 200 GPa\)
A
37.8 kN/m
B
19.8 kN/m
C
13 kN/m
D
15 kN/m
Answer: 15 kN/m
#19.
A simply supported beam is reinforced with 4-28 mm Φ at the top of the beam. Steel covering to centroid of reinforcements is 70 mm at the top and bottom of the beam. the beam has a total depth of 400 mm and a width of 300 mm. fc' = 300 MPa, fy = 415 MPa. Balanced steel ratio ρb=0.031.
Determine the depth of compression block.
A
86.55
B
96.55
C
76.45
D
106.45
Answer: 96.55