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    Topics || Problems

    Find the side of a square whose diagonal is 5 feet longer than a side.
    square with 5 feet longer than the side

    \( d = 5 + s\)

    Using the Pythagorean Theorem the diagonal is equal to \(s \sqrt{2}\)

    \( d= 5 +s =s \sqrt{2} \)

    \( 5 = s \sqrt{2} -s\)

    \( 5 = s ( \sqrt{2} -1)\)

    \( s = 5+5\sqrt{2}\)