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    Topics || Problems

    Simplify \( (\frac{b^{4x-3y}}{b^{3x+2y}})^{x} (\frac{b^{3x+6y}}{b^{-2x+4y}})^y\)

    Solution

    • \( (\frac{b^{4x-3y}}{b^{3x+2y}})^{x} (\frac{b^{3x+6y}}{b^{-2x+4y}})^y\) = \( (\frac{b^{4x}b^{-3y}}{b^{3x}b^{2y}})^x (\frac{b^{3x}b^{6y}}{b^{-2x}b^{4y}})^y\)

    • = \( (\frac{b^x}{b^5y})^x (b^{5x}b^{2y})^y\)

    • = \( (\frac{b^{x^2}}{b^{5xy}}) (b^{5xy}b^{2y^2})\)

    • = \( b^{x^2 +2y^2}\)