\(V_{cube} = s^3\)
\(TSA_{cube} = 6s^2\)
\(s^2 + s^2 = (2(12.7))^2\)
\(2s^2 = (25.4)^2\)
\(s =\frac {(25.4)}{\sqrt{2}}\)
\(Vol_{cube} =(\frac {(25.4)}{\sqrt{2}})^3 \)
\(Vol_{cube} =5793.70 in^3\)
\(TSA_{cube} = 6(\frac {(25.4)}{\sqrt{2}})^2\)
\(TSA_{cube} =1935.16 in^2\)