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    Topics || Problems

    Find the slope of the tangent line to the curve given by the equation \( y = 3x^2 +2x+ 1\) at x =2.

    Solution:

    Slope = \( \frac{dy}{dx} \)

    \( \frac{dy}{dx} = 6x +2 \)

    At x = 2

    \( \frac{dy}{dx} = 6(2) +2 \)

    \( \frac{dy}{dx} = 14 \)