Solution:
\( \frac{ds}{dt} = velocity \)
\( s = 14t^3 + 5t -1 \)
\( \frac{ds}{dt} = 42t^2 +5 \)
At t = 2
\( \frac{ds}{dt} = 42(2)^2 +5 \)
\( \frac{ds}{dt} = 173 \)