Let **x** be the units' digit and **y** be the tens' digit. Thus the number is 10y + x.

The units digit is 3 greater than the tens' digit: **x = 3 + y** (1)

The integer is 4 times as large as the sum of its digits: **4(x+y) = 10y + x** (2)

Substitute 1 to 2: 4(3 + y + y ) = 10y +3 + y

4(3 +2y ) = 11y +3

12 + 8 y = 11y +3

y = 3

x = 3 + 3 = 6

**Thus the integer is 10(3) + 6 = 36**