Solution:
Let \(x\) be the first part and \(y\) be the second part.
\(x+y = 80\)
\(\frac{x-4}{y-8}=\frac{1}{3}\)
\(3(x-4) = y-8\)
\(y = 80-x\)
\(3(x-4) =80-x-8\)
\(3x+x = 72 +12\)
\(x = 21\)
\(y = 80-21 = 59\)