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    Topics || Problems

    The sides of a triangle are 10, 9 and 15 inches long. In a similar triangle, the longest side is 21 inches long. Find the other side.

    Solution:

    Since the triangles are similar the ratio and proportion between their corresponding sides is possible.

    Let \(h \text{-shortest}\) and \(i\) be the lengths of the remaining side of the triangle.

    \(\frac{21}{h} = \frac{15}{9}\)

    \(h = \frac{21(9)}{15}\)

    \( h = 12.6\)

    \(\frac{21}{i} = \frac{15}{10}\)

    \(i = \frac{21(10)}{15}\)

    \(i = 14\)

    Thus, the length of the sides of the triangle are 14, 12.6 and 21 inches.