Math Notes

Subjects

Algebra Solutions

Topics || Problems

2. Find the dimensions of a rectangle where the altitude is four sevenths of the base and the perimeter is 330feet

Solutions:

let a be the altitude, b be the base and P be the perimeter.

P = 330

a = $$\frac{4}{7}$$ b

P = 2a+ 2b ; Formula for the perimeter of a rectangle

330 = (2)$$\frac{4}{7}$$b +2b

330 = $$\frac{8}{7}$$b + 2b

$$b = \frac{{330\left( 7 \right)}}{{8 + 14}}$$

b = 105 feet

a = $$\frac{4}{7}$$(105)

a = 60 feet