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    Topics || Problems

    If the smaller dimension of a rectangle is increased by 3 feet and the larger dimension by 5 feet, one dimension becomes \(\frac{3}{5}\) of the other, and the area is increased by 135 square feet. Find the original dimensions. Solution:
    Representations
    SymbolsMeaning
    \(L\)Length of the rectangle
    \(W\)Width of the rectangle
    \(L_n\)New length of the rectangle
    \(W_n\)New width of the rectangle

    \(L_n= L+5\)

    \(L = L_n -5\)

    \(W_n= W+3\)

    \(W = W_n -3\)

    \(W_n= \frac{3}{5} L_n\)

    \(W = \frac{3}{5} L_n -3\)

    \(A_n= A+135\)

    \(L_n W_n= LW+135\)

    \(L_n ( \frac{3}{5} L_n)= LW+135\)

    \(\frac{3}{5} L_n ^2= ( L_n -5)(\frac{3}{5}L_n -3)+135\)

    \(\frac{3}{5} L_n ^2= \frac{3}{5}L_n^2-3L_n -3L_n + 15)+135\)

    \(L_n = 25\)

    \(L = 25-5 = 20\)

    \(L = \frac{3}{5}(25)-3 = 12\)

    Thus the original dimensions is: 12x20 \text{feet}