Find the larger root of \(10x^2 -x = 3 \)

Solution

• \(10x^2 -x-3 = 0\)

• a = 10: b = -1: c = -3

• \(x_1 = \frac{--1+\sqrt{1^2-4(10)(-3)}}{2(10)} = \frac{3}{5}\)

• \(x_1 = \frac{--1-\sqrt{1^2-4(10)(-3)}}{2(10)} = \frac{-1}{2}\)

• Thus the larger root is \(\frac{3}{5}\)