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    Topics || Problems

    What is the graph of the equation \(18x^2 + 18 y^2 = 288\)
    Solution:

    The curve represents a circle at the origin, \(x^ +y^2 = r^2 \).

    Simplify the equation to its standard form: \(18x^2 + 18y^2 = 288\)

    \(x^2 + y^2 = 16\)

    Locate the center and the radius of the circle.

    The center of the circle is at the origin.

    \( r^2 = 16\)

    \( r = 4\)

    Graph the curve.

    circle with radius equal to 4