### Math Notes

Subjects

#### Analytic Geometry Solutions

##### Topics || Problems

Find the equation of the circle with center at (1,7) and radius equal to 3.

The standard equation of a circle is $$(x-h)+(y-k)^2=r^2$$, where $$(h,k)$$ is the origin and the $$r$$ is the radius.

$$(x-h)^2+(y-k)^2=r^2$$

$$(x-1)^2+(y-7)^2=3^2$$ Answer

To general form $$x^2-2x-1+y^2-14y +49 =9$$

$$x^2 + y^2 -2x -4y +39 =0$$