The standard equation of a circle is \((x-h)+(y-k)^2=r^2\), where \((h,k)\) is the origin and the \(r\) is the radius.

\((x-h)^2+(y-k)^2=r^2\)

\((x-1)^2+(y-7)^2=3^2\) Answer

To general form \(x^2-2x-1+y^2-14y +49 =9\)

\(x^2 + y^2 -2x -4y +39 =0\)