Math Notes

Subjects

Analytic Geometry Solutions

Topics || Problems

Find the line perpendicular to $$\frac{x}{3} + \frac{y}{4} =1$$
Solution

Slope, $$m = \frac{-4}{3}$$

Perpendicular slope, $$m_2 = \frac{3}{4}) Since the line is perpendicular to \( \frac{x}{3} + \frac{y}{4} =1$$ with no specified point, thus we can assume that the line will intersect the given line at $$(x_1, y_1)$$

$$(y-y_1) = \frac{3}{4} (x-x_1)$$

$$y = \frac{3}{4}x - \frac{3}{4}x_1 + y_1$$

$$4y = 3x + c$$

$$0 = 3x-4y +c$$, where $$c$$ is a constant value.