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    Topics || Problems

    A perimeter of a rectangle is 68 m and its diagonal is 26 m. What is the area of the rectangle?

    \( P = 2l + 2w \)

    \( 68 = 2l + 2w \)

    \( 34 -w = l \)

    \( A = lw \)

    \( d^2 = l^2 +w^2\)

    \( 26^2 = (34 -w)^2 + w^2 \)

    \( w = 10 m\)

    \( l = 24 m\)

    \( A = (24)(10) = 240 m^2 \)