Trigonometry Solutions
Topics || Problems
Points \(A\) and \(B\) are separated by an obstacle. In order to find the distance between them, a third point \(C\) is selected which is \(120 ~ yards\) from \(A\) and \(150~yards\) from \(B\). The angle \(ABC\) is measured to be \(80^o10'\). Find the distance from \(A\) to \(B\).
Let the distance between \(A\) and \(B\) be \(d\)
By cosine law, the value of \(d\) can be calculated.
Thus,
\(d^2 = 150^2 + 120^2 -2(150)(120)\cos{80^o10'}\)
\(d^2 = 30751.82\)
\(d = \sqrt{30751.82}\)
\(d \approx 175.36 ~yards\)